2b(4-6)+8=108

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Solution for 2b(4-6)+8=108 equation: 



2b(4-6)+8=108

We move all terms to the left:

2b(4-6)+8-(108)=0

We add all the numbers together, and all the variables

2b(-2)+8-108=0

We add all the numbers together, and all the variables

2b(-2)-100=0

We multiply parentheses

-4b-100=0

We move all terms containing b to the left, all other terms to the right

-4b=100

b=100/-4

b=-25

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