2b+(3b+42)+(b+18)=180

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Solution for 2b+(3b+42)+(b+18)=180 equation:



2b+(3b+42)+(b+18)=180
We move all terms to the left:
2b+(3b+42)+(b+18)-(180)=0
We get rid of parentheses
2b+3b+b+42+18-180=0
We add all the numbers together, and all the variables
6b-120=0
We move all terms containing b to the left, all other terms to the right
6b=120
b=120/6
b=20

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