2b+(3b-2)+(b+7)=65

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Solution for 2b+(3b-2)+(b+7)=65 equation:


Simplifying
2b + (3b + -2) + (b + 7) = 65

Reorder the terms:
2b + (-2 + 3b) + (b + 7) = 65

Remove parenthesis around (-2 + 3b)
2b + -2 + 3b + (b + 7) = 65

Reorder the terms:
2b + -2 + 3b + (7 + b) = 65

Remove parenthesis around (7 + b)
2b + -2 + 3b + 7 + b = 65

Reorder the terms:
-2 + 7 + 2b + 3b + b = 65

Combine like terms: -2 + 7 = 5
5 + 2b + 3b + b = 65

Combine like terms: 2b + 3b = 5b
5 + 5b + b = 65

Combine like terms: 5b + b = 6b
5 + 6b = 65

Solving
5 + 6b = 65

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 6b = 65 + -5

Combine like terms: 5 + -5 = 0
0 + 6b = 65 + -5
6b = 65 + -5

Combine like terms: 65 + -5 = 60
6b = 60

Divide each side by '6'.
b = 10

Simplifying
b = 10

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