2b+10(8+3b)=12(b+10)

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Solution for 2b+10(8+3b)=12(b+10) equation:


Simplifying
2b + 10(8 + 3b) = 12(b + 10)
2b + (8 * 10 + 3b * 10) = 12(b + 10)
2b + (80 + 30b) = 12(b + 10)

Reorder the terms:
80 + 2b + 30b = 12(b + 10)

Combine like terms: 2b + 30b = 32b
80 + 32b = 12(b + 10)

Reorder the terms:
80 + 32b = 12(10 + b)
80 + 32b = (10 * 12 + b * 12)
80 + 32b = (120 + 12b)

Solving
80 + 32b = 120 + 12b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-12b' to each side of the equation.
80 + 32b + -12b = 120 + 12b + -12b

Combine like terms: 32b + -12b = 20b
80 + 20b = 120 + 12b + -12b

Combine like terms: 12b + -12b = 0
80 + 20b = 120 + 0
80 + 20b = 120

Add '-80' to each side of the equation.
80 + -80 + 20b = 120 + -80

Combine like terms: 80 + -80 = 0
0 + 20b = 120 + -80
20b = 120 + -80

Combine like terms: 120 + -80 = 40
20b = 40

Divide each side by '20'.
b = 2

Simplifying
b = 2

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