2b+28=3(b+7)

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Solution for 2b+28=3(b+7) equation:



2b+28=3(b+7)
We move all terms to the left:
2b+28-(3(b+7))=0
We calculate terms in parentheses: -(3(b+7)), so:
3(b+7)
We multiply parentheses
3b+21
Back to the equation:
-(3b+21)
We get rid of parentheses
2b-3b-21+28=0
We add all the numbers together, and all the variables
-1b+7=0
We move all terms containing b to the left, all other terms to the right
-b=-7
b=-7/-1
b=+7

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