2b+3(1+26)=8b+12

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Solution for 2b+3(1+26)=8b+12 equation:



2b+3(1+26)=8b+12
We move all terms to the left:
2b+3(1+26)-(8b+12)=0
We add all the numbers together, and all the variables
2b-(8b+12)+327=0
We get rid of parentheses
2b-8b-12+327=0
We add all the numbers together, and all the variables
-6b+315=0
We move all terms containing b to the left, all other terms to the right
-6b=-315
b=-315/-6
b=52+1/2

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