2b+3(1+26)=8b+12

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Solution for 2b+3(1+26)=8b+12 equation: 



2b+3(1+26)=8b+12

We move all terms to the left:

2b+3(1+26)-(8b+12)=0

We add all the numbers together, and all the variables

2b-(8b+12)+327=0

We get rid of parentheses

2b-8b-12+327=0

We add all the numbers together, and all the variables

-6b+315=0

We move all terms containing b to the left, all other terms to the right

-6b=-315

b=-315/-6

b=52+1/2

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