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2b+5/3b+4=3
We move all terms to the left:
2b+5/3b+4-(3)=0
Domain of the equation: 3b!=0We add all the numbers together, and all the variables
b!=0/3
b!=0
b∈R
2b+5/3b+1=0
We multiply all the terms by the denominator
2b*3b+1*3b+5=0
Wy multiply elements
6b^2+3b+5=0
a = 6; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·6·5
Δ = -111
Delta is less than zero, so there is no solution for the equation
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