2b+6(3b+3)=158

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Solution for 2b+6(3b+3)=158 equation: 



2b+6(3b+3)=158

We move all terms to the left:

2b+6(3b+3)-(158)=0

We multiply parentheses

2b+18b+18-158=0

We add all the numbers together, and all the variables

20b-140=0

We move all terms containing b to the left, all other terms to the right

20b=140

b=140/20

b=7

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