2b-10=5(b+2)-1

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Solution for 2b-10=5(b+2)-1 equation: 



2b-10=5(b+2)-1

We move all terms to the left:

2b-10-(5(b+2)-1)=0



We calculate terms in parentheses: -(5(b+2)-1), so:

5(b+2)-1

We multiply parentheses

5b+10-1

We add all the numbers together, and all the variables

5b+9

Back to the equation:

-(5b+9)



We get rid of parentheses

2b-5b-9-10=0

We add all the numbers together, and all the variables

-3b-19=0

We move all terms containing b to the left, all other terms to the right

-3b=19

b=19/-3

b=-6+1/3

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