2b-3(4b+80)=100

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Solution for 2b-3(4b+80)=100 equation: 



2b-3(4b+80)=100

We move all terms to the left:

2b-3(4b+80)-(100)=0

We multiply parentheses

2b-12b-240-100=0

We add all the numbers together, and all the variables

-10b-340=0

We move all terms containing b to the left, all other terms to the right

-10b=340

b=340/-10

b=-34

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