2b-3(b-8)=5(b+6)

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Solution for 2b-3(b-8)=5(b+6) equation: 



2b-3(b-8)=5(b+6)

We move all terms to the left:

2b-3(b-8)-(5(b+6))=0

We multiply parentheses

2b-3b-(5(b+6))+24=0



We calculate terms in parentheses: -(5(b+6)), so:

5(b+6)

We multiply parentheses

5b+30

Back to the equation:

-(5b+30)



We add all the numbers together, and all the variables

-1b-(5b+30)+24=0

We get rid of parentheses

-1b-5b-30+24=0

We add all the numbers together, and all the variables

-6b-6=0

We move all terms containing b to the left, all other terms to the right

-6b=6

b=6/-6

b=-1

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