2b-3/b=b-10/b

Solution for 2b-3/b=b-10/b equation:

2b-3/b=b-10/b

We move all terms to the left:

2b-3/b-(b-10/b)=0


Domain of the equation: b!=0

b∈R



Domain of the equation: b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

2b-3/b-(+b-10/b)=0

We get rid of parentheses

2b-3/b-b+10/b=0

We multiply all the terms by the denominator


2b*b-b*b-3+10=0

We add all the numbers together, and all the variables

2b*b-b*b+7=0

Wy multiply elements

2b^2-1b^2+7=0

We add all the numbers together, and all the variables

b^2+7=0

a = 1; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·1·7
Δ = -28
Delta is less than zero, so there is no solution for the equation