2b-4(10)=5(b-5)

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Solution for 2b-4(10)=5(b-5) equation: 



2b-4(10)=5(b-5)

We move all terms to the left:

2b-4(10)-(5(b-5))=0



We calculate terms in parentheses: -(5(b-5)), so:

5(b-5)

We multiply parentheses

5b-25

Back to the equation:

-(5b-25)



We get rid of parentheses

2b-5b+25-410=0

We add all the numbers together, and all the variables

-3b-385=0

We move all terms containing b to the left, all other terms to the right

-3b=385

b=385/-3

b=-128+1/3

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