2b-7=3+3(b-2)

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Solution for 2b-7=3+3(b-2) equation: 



2b-7=3+3(b-2)

We move all terms to the left:

2b-7-(3+3(b-2))=0



We calculate terms in parentheses: -(3+3(b-2)), so:

3+3(b-2)

determiningTheFunctionDomain
3(b-2)+3

We multiply parentheses

3b-6+3

We add all the numbers together, and all the variables

3b-3

Back to the equation:

-(3b-3)



We get rid of parentheses

2b-3b+3-7=0

We add all the numbers together, and all the variables

-1b-4=0

We move all terms containing b to the left, all other terms to the right

-b=4

b=4/-1

b=-4

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