2b/3b+1=-3b/4b+2

Solution for 2b/3b+1=-3b/4b+2 equation:

2b/3b+1=-3b/4b+2

We move all terms to the left:

2b/3b+1-(-3b/4b+2)=0


Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



Domain of the equation: 4b+2)!=0

b∈R


We get rid of parentheses

2b/3b+3b/4b-2+1=0

We calculate fractions


8b^2/12b^2+9b^2/12b^2-2+1=0

We add all the numbers together, and all the variables

8b^2/12b^2+9b^2/12b^2-1=0

We multiply all the terms by the denominator


8b^2+9b^2-1*12b^2=0

We add all the numbers together, and all the variables

17b^2-1*12b^2=0

Wy multiply elements

17b^2-12b^2=0

We add all the numbers together, and all the variables

5b^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{10}=0$