2b2+14b=-24

Solution for 2b2+14b=-24 equation:

2b^2+14b=-24

We move all terms to the left:

2b^2+14b-(-24)=0

We add all the numbers together, and all the variables

2b^2+14b+24=0

a = 2; b = 14; c = +24;
Δ = b2-4ac
Δ = 142-4·2·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*2}=\frac{-16}{4}
=-4
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*2}=\frac{-12}{4}
=-3
$