2c(3c-4)=5c-4

Solution for 2c(3c-4)=5c-4 equation:

2c(3c-4)=5c-4

We move all terms to the left:

2c(3c-4)-(5c-4)=0

We multiply parentheses

6c^2-8c-(5c-4)=0

We get rid of parentheses

6c^2-8c-5c+4=0

We add all the numbers together, and all the variables

6c^2-13c+4=0

a = 6; b = -13; c = +4;
Δ = b2-4ac
Δ = -132-4·6·4
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{73}}{2*6}=\frac{13-\sqrt{73}}{12}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{73}}{2*6}=\frac{13+\sqrt{73}}{12}
$