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2c(c-14)=0
We multiply parentheses
2c^2-28c=0
a = 2; b = -28; c = 0;
Δ = b2-4ac
Δ = -282-4·2·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-28}{2*2}=\frac{0}{4} =0 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+28}{2*2}=\frac{56}{4} =14 $
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