2c(c-5)=c(2c-5)-5

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Solution for 2c(c-5)=c(2c-5)-5 equation: 


Simplifying
2c(c + -5) = c(2c + -5) + -5

Reorder the terms:
2c(-5 + c) = c(2c + -5) + -5
(-5 * 2c + c * 2c) = c(2c + -5) + -5
(-10c + 2c2) = c(2c + -5) + -5

Reorder the terms:
-10c + 2c2 = c(-5 + 2c) + -5
-10c + 2c2 = (-5 * c + 2c * c) + -5
-10c + 2c2 = (-5c + 2c2) + -5

Reorder the terms:
-10c + 2c2 = -5 + -5c + 2c2

Add '-2c2' to each side of the equation.
-10c + 2c2 + -2c2 = -5 + -5c + 2c2 + -2c2

Combine like terms: 2c2 + -2c2 = 0
-10c + 0 = -5 + -5c + 2c2 + -2c2
-10c = -5 + -5c + 2c2 + -2c2

Combine like terms: 2c2 + -2c2 = 0
-10c = -5 + -5c + 0
-10c = -5 + -5c

Solving
-10c = -5 + -5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '5c' to each side of the equation.
-10c + 5c = -5 + -5c + 5c

Combine like terms: -10c + 5c = -5c
-5c = -5 + -5c + 5c

Combine like terms: -5c + 5c = 0
-5c = -5 + 0
-5c = -5

Divide each side by '-5'.
c = 1

Simplifying
c = 1

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