2c+(3c-4)=(-4c)-4

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Solution for 2c+(3c-4)=(-4c)-4 equation: 



2c+(3c-4)=(-4c)-4

We move all terms to the left:

2c+(3c-4)-((-4c)-4)=0

We get rid of parentheses

2c+3c-((-4c)-4)-4=0



We calculate terms in parentheses: -((-4c)-4), so:

(-4c)-4

We get rid of parentheses

-4c-4

Back to the equation:

-(-4c-4)



We add all the numbers together, and all the variables

5c-(-4c-4)-4=0

We get rid of parentheses

5c+4c+4-4=0

We add all the numbers together, and all the variables

9c=0

c=0/9

c=0

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