2c+-3=2(6+-c)+7c

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Solution for 2c+-3=2(6+-c)+7c equation: 



2c+-3=2(6+-c)+7c

We move all terms to the left:

2c+-3-(2(6+-c)+7c)=0

We add all the numbers together, and all the variables

2c-(2(-1c)+7c)-3+=0

We add all the numbers together, and all the variables

2c-(2(-1c)+7c)=0



We calculate terms in parentheses: -(2(-1c)+7c), so:

2(-1c)+7c

We add all the numbers together, and all the variables

7c+2(-1c)

We multiply parentheses

7c-2c

We add all the numbers together, and all the variables

5c

Back to the equation:

-(5c)



We add all the numbers together, and all the variables

-3c=0

c=0/-3

c=0

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