2c+-3=2(6-c)+7c

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Solution for 2c+-3=2(6-c)+7c equation: 



2c+-3=2(6-c)+7c

We move all terms to the left:

2c+-3-(2(6-c)+7c)=0

We add all the numbers together, and all the variables

2c-(2(-1c+6)+7c)-3+=0

We add all the numbers together, and all the variables

2c-(2(-1c+6)+7c)=0



We calculate terms in parentheses: -(2(-1c+6)+7c), so:

2(-1c+6)+7c

We add all the numbers together, and all the variables

7c+2(-1c+6)

We multiply parentheses

7c-2c+12

We add all the numbers together, and all the variables

5c+12

Back to the equation:

-(5c+12)



We get rid of parentheses

2c-5c-12=0

We add all the numbers together, and all the variables

-3c-12=0

We move all terms containing c to the left, all other terms to the right

-3c=12

c=12/-3

c=-4

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