2c+-6(-2c+2)=-82+4c

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Solution for 2c+-6(-2c+2)=-82+4c equation:



2c+-6(-2c+2)=-82+4c
We move all terms to the left:
2c+-6(-2c+2)-(-82+4c)=0
We add all the numbers together, and all the variables
2c-6(-2c+2)-(4c-82)+=0
We add all the numbers together, and all the variables
2c-6(-2c+2)-(4c-82)=0
We multiply parentheses
2c+12c-(4c-82)-12=0
We get rid of parentheses
2c+12c-4c+82-12=0
We add all the numbers together, and all the variables
10c+70=0
We move all terms containing c to the left, all other terms to the right
10c=-70
c=-70/10
c=-7

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