2c+2(3c-2)=2c+2(4c+6)

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Solution for 2c+2(3c-2)=2c+2(4c+6) equation: 



2c+2(3c-2)=2c+2(4c+6)

We move all terms to the left:

2c+2(3c-2)-(2c+2(4c+6))=0

We multiply parentheses

2c+6c-(2c+2(4c+6))-4=0



We calculate terms in parentheses: -(2c+2(4c+6)), so:

2c+2(4c+6)

We multiply parentheses

2c+8c+12

We add all the numbers together, and all the variables

10c+12

Back to the equation:

-(10c+12)



We add all the numbers together, and all the variables

8c-(10c+12)-4=0

We get rid of parentheses

8c-10c-12-4=0

We add all the numbers together, and all the variables

-2c-16=0

We move all terms containing c to the left, all other terms to the right

-2c=16

c=16/-2

c=-8

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