2c+2(c-6)=76

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Solution for 2c+2(c-6)=76 equation: 



2c+2(c-6)=76

We move all terms to the left:

2c+2(c-6)-(76)=0

We multiply parentheses

2c+2c-12-76=0

We add all the numbers together, and all the variables

4c-88=0

We move all terms containing c to the left, all other terms to the right

4c=88

c=88/4

c=22

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