2c+21=7c+2(6-c)

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Solution for 2c+21=7c+2(6-c) equation: 



2c+21=7c+2(6-c)

We move all terms to the left:

2c+21-(7c+2(6-c))=0

We add all the numbers together, and all the variables

2c-(7c+2(-1c+6))+21=0



We calculate terms in parentheses: -(7c+2(-1c+6)), so:

7c+2(-1c+6)

We multiply parentheses

7c-2c+12

We add all the numbers together, and all the variables

5c+12

Back to the equation:

-(5c+12)



We get rid of parentheses

2c-5c-12+21=0

We add all the numbers together, and all the variables

-3c+9=0

We move all terms containing c to the left, all other terms to the right

-3c=-9

c=-9/-3

c=+3

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