2c+3c-4=(-1c)-4

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Solution for 2c+3c-4=(-1c)-4 equation: 



2c+3c-4=(-1c)-4

We move all terms to the left:

2c+3c-4-((-1c)-4)=0

We add all the numbers together, and all the variables

5c-((-1c)-4)-4=0



We calculate terms in parentheses: -((-1c)-4), so:

(-1c)-4

We get rid of parentheses

-1c-4

Back to the equation:

-(-1c-4)



We get rid of parentheses

5c+1c+4-4=0

We add all the numbers together, and all the variables

6c=0

c=0/6

c=0

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