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2c+4(2c+3)=102
We move all terms to the left:
2c+4(2c+3)-(102)=0
We multiply parentheses
2c+8c+12-102=0
We add all the numbers together, and all the variables
10c-90=0
We move all terms containing c to the left, all other terms to the right
10c=90
c=90/10
c=9
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