2c+4(c-5)=10

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Solution for 2c+4(c-5)=10 equation: 



2c+4(c-5)=10

We move all terms to the left:

2c+4(c-5)-(10)=0

We multiply parentheses

2c+4c-20-10=0

We add all the numbers together, and all the variables

6c-30=0

We move all terms containing c to the left, all other terms to the right

6c=30

c=30/6

c=5

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