2c+4c-11=6(c-2)

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Solution for 2c+4c-11=6(c-2) equation:


Simplifying
2c + 4c + -11 = 6(c + -2)

Reorder the terms:
-11 + 2c + 4c = 6(c + -2)

Combine like terms: 2c + 4c = 6c
-11 + 6c = 6(c + -2)

Reorder the terms:
-11 + 6c = 6(-2 + c)
-11 + 6c = (-2 * 6 + c * 6)
-11 + 6c = (-12 + 6c)

Add '-6c' to each side of the equation.
-11 + 6c + -6c = -12 + 6c + -6c

Combine like terms: 6c + -6c = 0
-11 + 0 = -12 + 6c + -6c
-11 = -12 + 6c + -6c

Combine like terms: 6c + -6c = 0
-11 = -12 + 0
-11 = -12

Solving
-11 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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