2c-(1c+6)=4(1c-2)

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Solution for 2c-(1c+6)=4(1c-2) equation:


Simplifying
2c + -1(1c + 6) = 4(1c + -2)

Reorder the terms:
2c + -1(6 + 1c) = 4(1c + -2)
2c + (6 * -1 + 1c * -1) = 4(1c + -2)
2c + (-6 + -1c) = 4(1c + -2)

Reorder the terms:
-6 + 2c + -1c = 4(1c + -2)

Combine like terms: 2c + -1c = 1c
-6 + 1c = 4(1c + -2)

Reorder the terms:
-6 + 1c = 4(-2 + 1c)
-6 + 1c = (-2 * 4 + 1c * 4)
-6 + 1c = (-8 + 4c)

Solving
-6 + 1c = -8 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-6 + 1c + -4c = -8 + 4c + -4c

Combine like terms: 1c + -4c = -3c
-6 + -3c = -8 + 4c + -4c

Combine like terms: 4c + -4c = 0
-6 + -3c = -8 + 0
-6 + -3c = -8

Add '6' to each side of the equation.
-6 + 6 + -3c = -8 + 6

Combine like terms: -6 + 6 = 0
0 + -3c = -8 + 6
-3c = -8 + 6

Combine like terms: -8 + 6 = -2
-3c = -2

Divide each side by '-3'.
c = 0.6666666667

Simplifying
c = 0.6666666667

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