2c-100+c=c+50+(2c-100)-20

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Solution for 2c-100+c=c+50+(2c-100)-20 equation: 


Simplifying
2c + -100 + c = c + 50 + (2c + -100) + -20

Reorder the terms:
-100 + 2c + c = c + 50 + (2c + -100) + -20

Combine like terms: 2c + c = 3c
-100 + 3c = c + 50 + (2c + -100) + -20

Reorder the terms:
-100 + 3c = c + 50 + (-100 + 2c) + -20

Remove parenthesis around (-100 + 2c)
-100 + 3c = c + 50 + -100 + 2c + -20

Reorder the terms:
-100 + 3c = 50 + -100 + -20 + c + 2c

Combine like terms: 50 + -100 = -50
-100 + 3c = -50 + -20 + c + 2c

Combine like terms: -50 + -20 = -70
-100 + 3c = -70 + c + 2c

Combine like terms: c + 2c = 3c
-100 + 3c = -70 + 3c

Add '-3c' to each side of the equation.
-100 + 3c + -3c = -70 + 3c + -3c

Combine like terms: 3c + -3c = 0
-100 + 0 = -70 + 3c + -3c
-100 = -70 + 3c + -3c

Combine like terms: 3c + -3c = 0
-100 = -70 + 0
-100 = -70

Solving
-100 = -70

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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