2c-2(3-8c)=3c-48

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Solution for 2c-2(3-8c)=3c-48 equation: 



2c-2(3-8c)=3c-48

We move all terms to the left:

2c-2(3-8c)-(3c-48)=0

We add all the numbers together, and all the variables

2c-2(-8c+3)-(3c-48)=0

We multiply parentheses

2c+16c-(3c-48)-6=0

We get rid of parentheses

2c+16c-3c+48-6=0

We add all the numbers together, and all the variables

15c+42=0

We move all terms containing c to the left, all other terms to the right

15c=-42

c=-42/15

c=-2+4/5

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