2c-3(c+1)=2(c+3)

Solution for 2c-3(c+1)=2(c+3) equation:

Simplifying
2c + -3(c + 1) = 2(c + 3)

Reorder the terms:
2c + -3(1 + c) = 2(c + 3)
2c + (1 * -3 + c * -3) = 2(c + 3)
2c + (-3 + -3c) = 2(c + 3)

Reorder the terms:
-3 + 2c + -3c = 2(c + 3)

Combine like terms: 2c + -3c = -1c
-3 + -1c = 2(c + 3)

Reorder the terms:
-3 + -1c = 2(3 + c)
-3 + -1c = (3 * 2 + c * 2)
-3 + -1c = (6 + 2c)

Solving
-3 + -1c = 6 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-3 + -1c + -2c = 6 + 2c + -2c

Combine like terms: -1c + -2c = -3c
-3 + -3c = 6 + 2c + -2c

Combine like terms: 2c + -2c = 0
-3 + -3c = 6 + 0
-3 + -3c = 6

Add '3' to each side of the equation.
-3 + 3 + -3c = 6 + 3

Combine like terms: -3 + 3 = 0
0 + -3c = 6 + 3
-3c = 6 + 3

Combine like terms: 6 + 3 = 9
-3c = 9

Divide each side by '-3'.
c = -3

Simplifying
c = -3