2c-3=12(6-c)+7c

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Solution for 2c-3=12(6-c)+7c equation: 



2c-3=12(6-c)+7c

We move all terms to the left:

2c-3-(12(6-c)+7c)=0

We add all the numbers together, and all the variables

2c-(12(-1c+6)+7c)-3=0



We calculate terms in parentheses: -(12(-1c+6)+7c), so:

12(-1c+6)+7c

We add all the numbers together, and all the variables

7c+12(-1c+6)

We multiply parentheses

7c-12c+72

We add all the numbers together, and all the variables

-5c+72

Back to the equation:

-(-5c+72)



We get rid of parentheses

2c+5c-72-3=0

We add all the numbers together, and all the variables

7c-75=0

We move all terms containing c to the left, all other terms to the right

7c=75

c=75/7

c=10+5/7

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