2c-3=2(6-c)+7

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Solution for 2c-3=2(6-c)+7 equation: 



2c-3=2(6-c)+7

We move all terms to the left:

2c-3-(2(6-c)+7)=0

We add all the numbers together, and all the variables

2c-(2(-1c+6)+7)-3=0



We calculate terms in parentheses: -(2(-1c+6)+7), so:

2(-1c+6)+7

We multiply parentheses

-2c+12+7

We add all the numbers together, and all the variables

-2c+19

Back to the equation:

-(-2c+19)



We get rid of parentheses

2c+2c-19-3=0

We add all the numbers together, and all the variables

4c-22=0

We move all terms containing c to the left, all other terms to the right

4c=22

c=22/4

c=5+1/2

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