2c-3=2(6-c)+7

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Solution for 2c-3=2(6-c)+7 equation:



2c-3=2(6-c)+7
We move all terms to the left:
2c-3-(2(6-c)+7)=0
We add all the numbers together, and all the variables
2c-(2(-1c+6)+7)-3=0
We calculate terms in parentheses: -(2(-1c+6)+7), so:
2(-1c+6)+7
We multiply parentheses
-2c+12+7
We add all the numbers together, and all the variables
-2c+19
Back to the equation:
-(-2c+19)
We get rid of parentheses
2c+2c-19-3=0
We add all the numbers together, and all the variables
4c-22=0
We move all terms containing c to the left, all other terms to the right
4c=22
c=22/4
c=5+1/2

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