2c-3=2(6-c+7c)

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Solution for 2c-3=2(6-c+7c) equation:



2c-3=2(6-c+7c)
We move all terms to the left:
2c-3-(2(6-c+7c))=0
We add all the numbers together, and all the variables
2c-(2(6c+6))-3=0
We calculate terms in parentheses: -(2(6c+6)), so:
2(6c+6)
We multiply parentheses
12c+12
Back to the equation:
-(12c+12)
We get rid of parentheses
2c-12c-12-3=0
We add all the numbers together, and all the variables
-10c-15=0
We move all terms containing c to the left, all other terms to the right
-10c=15
c=15/-10
c=-1+1/2

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