2c-4c+8=c-1

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Solution for 2c-4c+8=c-1 equation: 



2c-4c+8=c-1

We move all terms to the left:

2c-4c+8-(c-1)=0

We add all the numbers together, and all the variables

-2c-(c-1)+8=0

We get rid of parentheses

-2c-c+1+8=0

We add all the numbers together, and all the variables

-3c+9=0

We move all terms containing c to the left, all other terms to the right

-3c=-9

c=-9/-3

c=+3

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