2c-5(c-3)=2(c-10)

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Solution for 2c-5(c-3)=2(c-10) equation:


Simplifying
2c + -5(c + -3) = 2(c + -10)

Reorder the terms:
2c + -5(-3 + c) = 2(c + -10)
2c + (-3 * -5 + c * -5) = 2(c + -10)
2c + (15 + -5c) = 2(c + -10)

Reorder the terms:
15 + 2c + -5c = 2(c + -10)

Combine like terms: 2c + -5c = -3c
15 + -3c = 2(c + -10)

Reorder the terms:
15 + -3c = 2(-10 + c)
15 + -3c = (-10 * 2 + c * 2)
15 + -3c = (-20 + 2c)

Solving
15 + -3c = -20 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
15 + -3c + -2c = -20 + 2c + -2c

Combine like terms: -3c + -2c = -5c
15 + -5c = -20 + 2c + -2c

Combine like terms: 2c + -2c = 0
15 + -5c = -20 + 0
15 + -5c = -20

Add '-15' to each side of the equation.
15 + -15 + -5c = -20 + -15

Combine like terms: 15 + -15 = 0
0 + -5c = -20 + -15
-5c = -20 + -15

Combine like terms: -20 + -15 = -35
-5c = -35

Divide each side by '-5'.
c = 7

Simplifying
c = 7

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