2c-5+10=27-2

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Solution for 2c-5+10=27-2 equation: 



2c-5+10=27-2

We move all terms to the left:

2c-5+10-(27-2)=0

We add all the numbers together, and all the variables

2c-5+10-25=0

We add all the numbers together, and all the variables

2c-20=0

We move all terms containing c to the left, all other terms to the right

2c=20

c=20/2

c=10

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