2c-8(-7+4c)=3c+5c

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Solution for 2c-8(-7+4c)=3c+5c equation: 



2c-8(-7+4c)=3c+5c

We move all terms to the left:

2c-8(-7+4c)-(3c+5c)=0

We add all the numbers together, and all the variables

2c-8(4c-7)-(+8c)=0

We multiply parentheses

2c-32c-(+8c)+56=0

We get rid of parentheses

2c-32c-8c+56=0

We add all the numbers together, and all the variables

-38c+56=0

We move all terms containing c to the left, all other terms to the right

-38c=-56

c=-56/-38

c=1+9/19

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