2c=-2(2c+1)+8

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Solution for 2c=-2(2c+1)+8 equation: 



2c=-2(2c+1)+8

We move all terms to the left:

2c-(-2(2c+1)+8)=0



We calculate terms in parentheses: -(-2(2c+1)+8), so:

-2(2c+1)+8

We multiply parentheses

-4c-2+8

We add all the numbers together, and all the variables

-4c+6

Back to the equation:

-(-4c+6)



We get rid of parentheses

2c+4c-6=0

We add all the numbers together, and all the variables

6c-6=0

We move all terms containing c to the left, all other terms to the right

6c=6

c=6/6

c=1

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