2ci+1=-d+6-ci

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Solution for 2ci+1=-d+6-ci equation:


Simplifying
2ci + 1 = -1d + 6 + -1ci

Reorder the terms:
1 + 2ci = -1d + 6 + -1ci

Reorder the terms:
1 + 2ci = 6 + -1ci + -1d

Solving
1 + 2ci = 6 + -1ci + -1d

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add 'ci' to each side of the equation.
1 + 2ci + ci = 6 + -1ci + ci + -1d

Combine like terms: 2ci + ci = 3ci
1 + 3ci = 6 + -1ci + ci + -1d

Combine like terms: -1ci + ci = 0
1 + 3ci = 6 + 0 + -1d
1 + 3ci = 6 + -1d

Add '-1' to each side of the equation.
1 + -1 + 3ci = 6 + -1 + -1d

Combine like terms: 1 + -1 = 0
0 + 3ci = 6 + -1 + -1d
3ci = 6 + -1 + -1d

Combine like terms: 6 + -1 = 5
3ci = 5 + -1d

Divide each side by '3i'.
c = 1.666666667i-1 + -0.3333333333di-1

Simplifying
c = 1.666666667i-1 + -0.3333333333di-1

Reorder the terms:
c = -0.3333333333di-1 + 1.666666667i-1

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