2cos(2x)+10sin(2x)=5

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Solution for 2cos(2x)+10sin(2x)=5 equation:


Simplifying
2cos(2x) + 10sin(2x) = 5

Remove parenthesis around (2x)
2cos * 2x + 10sin(2x) = 5

Reorder the terms for easier multiplication:
2 * 2cos * x + 10sin(2x) = 5

Multiply 2 * 2
4cos * x + 10sin(2x) = 5

Multiply cos * x
4cosx + 10sin(2x) = 5

Remove parenthesis around (2x)
4cosx + 10ins * 2x = 5

Reorder the terms for easier multiplication:
4cosx + 10 * 2ins * x = 5

Multiply 10 * 2
4cosx + 20ins * x = 5

Multiply ins * x
4cosx + 20insx = 5

Solving
4cosx + 20insx = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-20insx' to each side of the equation.
4cosx + 20insx + -20insx = 5 + -20insx

Combine like terms: 20insx + -20insx = 0
4cosx + 0 = 5 + -20insx
4cosx = 5 + -20insx

Divide each side by '4osx'.
c = 1.25o-1s-1x-1 + -5ino-1

Simplifying
c = 1.25o-1s-1x-1 + -5ino-1

Reorder the terms:
c = -5ino-1 + 1.25o-1s-1x-1

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