2cos(2x)+3=14cos(x)-5

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Solution for 2cos(2x)+3=14cos(x)-5 equation:


Simplifying
2cos(2x) + 3 = 14cos(x) + -5

Remove parenthesis around (2x)
2cos * 2x + 3 = 14cos(x) + -5

Reorder the terms for easier multiplication:
2 * 2cos * x + 3 = 14cos(x) + -5

Multiply 2 * 2
4cos * x + 3 = 14cos(x) + -5

Multiply cos * x
4cosx + 3 = 14cos(x) + -5

Reorder the terms:
3 + 4cosx = 14cos(x) + -5

Multiply cos * x
3 + 4cosx = 14cosx + -5

Reorder the terms:
3 + 4cosx = -5 + 14cosx

Solving
3 + 4cosx = -5 + 14cosx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-14cosx' to each side of the equation.
3 + 4cosx + -14cosx = -5 + 14cosx + -14cosx

Combine like terms: 4cosx + -14cosx = -10cosx
3 + -10cosx = -5 + 14cosx + -14cosx

Combine like terms: 14cosx + -14cosx = 0
3 + -10cosx = -5 + 0
3 + -10cosx = -5

Add '-3' to each side of the equation.
3 + -3 + -10cosx = -5 + -3

Combine like terms: 3 + -3 = 0
0 + -10cosx = -5 + -3
-10cosx = -5 + -3

Combine like terms: -5 + -3 = -8
-10cosx = -8

Divide each side by '-10osx'.
c = 0.8o-1s-1x-1

Simplifying
c = 0.8o-1s-1x-1

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