2cos(2x)+sin(2x)=1

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Solution for 2cos(2x)+sin(2x)=1 equation: 


Simplifying
2cos(2x) + sin(2x) = 1

Remove parenthesis around (2x)
2cos * 2x + sin(2x) = 1

Reorder the terms for easier multiplication:
2 * 2cos * x + sin(2x) = 1

Multiply 2 * 2
4cos * x + sin(2x) = 1

Multiply cos * x
4cosx + sin(2x) = 1

Remove parenthesis around (2x)
4cosx + ins * 2x = 1

Reorder the terms for easier multiplication:
4cosx + 2ins * x = 1

Multiply ins * x
4cosx + 2insx = 1

Solving
4cosx + 2insx = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2insx' to each side of the equation.
4cosx + 2insx + -2insx = 1 + -2insx

Combine like terms: 2insx + -2insx = 0
4cosx + 0 = 1 + -2insx
4cosx = 1 + -2insx

Divide each side by '4osx'.
c = 0.25o-1s-1x-1 + -0.5ino-1

Simplifying
c = 0.25o-1s-1x-1 + -0.5ino-1

Reorder the terms:
c = -0.5ino-1 + 0.25o-1s-1x-1

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