2cos(3x)-3cos(3x)+1=0

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Solution for 2cos(3x)-3cos(3x)+1=0 equation:


Simplifying
2cos(3x) + -3cos(3x) + 1 = 0

Remove parenthesis around (3x)
2cos * 3x + -3cos(3x) + 1 = 0

Reorder the terms for easier multiplication:
2 * 3cos * x + -3cos(3x) + 1 = 0

Multiply 2 * 3
6cos * x + -3cos(3x) + 1 = 0

Multiply cos * x
6cosx + -3cos(3x) + 1 = 0

Remove parenthesis around (3x)
6cosx + -3cos * 3x + 1 = 0

Reorder the terms for easier multiplication:
6cosx + -3 * 3cos * x + 1 = 0

Multiply -3 * 3
6cosx + -9cos * x + 1 = 0

Multiply cos * x
6cosx + -9cosx + 1 = 0

Reorder the terms:
1 + 6cosx + -9cosx = 0

Combine like terms: 6cosx + -9cosx = -3cosx
1 + -3cosx = 0

Solving
1 + -3cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -3cosx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3cosx = 0 + -1
-3cosx = 0 + -1

Combine like terms: 0 + -1 = -1
-3cosx = -1

Divide each side by '-3osx'.
c = 0.3333333333o-1s-1x-1

Simplifying
c = 0.3333333333o-1s-1x-1

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