2d+(8-5)=10(5-2+d)

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Solution for 2d+(8-5)=10(5-2+d) equation:



2d+(8-5)=10(5-2+d)
We move all terms to the left:
2d+(8-5)-(10(5-2+d))=0
We add all the numbers together, and all the variables
2d-(10(d+3))+3=0
We calculate terms in parentheses: -(10(d+3)), so:
10(d+3)
We multiply parentheses
10d+30
Back to the equation:
-(10d+30)
We get rid of parentheses
2d-10d-30+3=0
We add all the numbers together, and all the variables
-8d-27=0
We move all terms containing d to the left, all other terms to the right
-8d=27
d=27/-8
d=-3+3/8

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