2d+1/6=6(1/3d)+1

Solution for 2d+1/6=6(1/3d)+1 equation:

2d+1/6=6(1/3d)+1

We move all terms to the left:

2d+1/6-(6(1/3d)+1)=0


Domain of the equation: 3d)+1)!=0

d!=0/1

d!=0

d∈R


We add all the numbers together, and all the variables

2d-(6(+1/3d)+1)+1/6=0

We calculate fractions


2d+()/3d+1)*6)+3d/3d+1)*6)=0

We calculate fractions


2d+(()*3d)/9d^2+1*6)+3d*3d)/9d^2=0

We multiply all the terms by the denominator


2d*9d^2+(()*3d)+1*6)+3d*3d)=0


We calculate terms in parentheses: +(()*3d), so:

()*3d


Wy multiply elements

18d^3+18d^2+(()*3d)=0


We calculate terms in parentheses: +(()*3d), so:

()*3d


We do not support edpression: d^3