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2d+12/d=24
We move all terms to the left:
2d+12/d-(24)=0
Domain of the equation: d!=0We multiply all the terms by the denominator
d∈R
2d*d-24*d+12=0
We add all the numbers together, and all the variables
-24d+2d*d+12=0
Wy multiply elements
2d^2-24d+12=0
a = 2; b = -24; c = +12;
Δ = b2-4ac
Δ = -242-4·2·12
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{30}}{2*2}=\frac{24-4\sqrt{30}}{4} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{30}}{2*2}=\frac{24+4\sqrt{30}}{4} $
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